In PHP, passing parameters by reference to a function means that instead of passing a copy of the variable’s value to the function, you’re passing the actual variable itself. This allows the function to modify the original variable. This is done by prefixing the parameter with an ampersand (&) in the function definition.
Here is the technical description and examples of how to pass parameters by reference in PHP:
```
function addFive(&$num) {
$num += 5;
}
$number = 10;
echo “Before function call: $number\n”; // Outputs: 10
addFive($number);
echo “After function call: $number\n”; // Outputs: 15
?>
```
In the above example:
1. We define a function `addFive` that expects a parameter to be passed by reference (indicated by the `&`).
2. We then call this function with the variable `$number`.
3. Inside the function, `$num` is a reference to `$number` in the calling scope. Thus, changes to `$num` affect `$number`.
If you don’t pass the variable by reference, the original value won’t be altered:
```
function addFive($num) {
$num += 5;
}
$number = 10;
echo “Before function call: $number\n”; // Outputs: 10
addFive($number);
echo “After function call: $number\n”; // Outputs: 10
?>
```
1. Modifying Arrays: This is particularly useful when dealing with large arrays or objects where copying them would be resource-intensive.
\`\`\`php 1 [1] => 2 [2] => 3 [3] => 4 ) ?> \`\`\`
These sources provide comprehensive information on PHP functions, including how to pass parameters by reference, offering further examples and detailed explanations.